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\begin{document}

\begin{tabular}{lr}
	Name:\underline{\hspace{8cm}}  & Math 095 Midterm I (C) \\
	& \hspace{3cm} 3 March 2011
\end{tabular}

\vspace{1cm}
\textbf{Section I}  Plot the expression on the number line.  (3 pts. each)
\vspace{.5cm}\\

\begin{tabular}{ll}
\prob	$a = -\frac{3}{4}$ & \prob	$x < 2$ \\
\vspace{.5cm}
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&
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	\psaxes[subticks=0,labels=none]{<->}(0,0)(8,5)(-8,-5)%
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\prob	$x \geq 0$ & \prob	$-2 \leq x < 5$ \\
\vspace{.5cm}
\begin{pspicture}(-8,-0.5)(8,1)
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	\psaxes[subticks=0,labels=none]{<->}(0,0)(8,5)(-8,-5)%
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&
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	\psset{yAxis=false}%
	\psaxes[subticks=0,labels=none]{<->}(0,0)(8,5)(-8,-5)%
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\prob	$x \in [-1,\infty)$  & \\
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&\\
\end{tabular}\\

\vspace{1cm}
\textbf{Section II}  Identify the algebraic fact that justifies the equality .  (3 pts. each)
\vspace{.5cm}\\

\begin{tabular}{ll}
\vspace{1cm}
\prob	$(x+6)+z^2=x+(6+z^2)$ &\prob	$7(t-4)=(t-4)7$\\
\vspace{1cm}
\prob	$\frac{3}{2}=\frac{7}{7}\frac{3}{2}$ &\prob	$(-a + a)+6=6$\\
\vspace{1cm}
\prob	$(x+6)(x-2)=x(x-2)+6(x-2)$\hspace{2cm} &\prob	$(\frac{1}{t}t)x=x$\\
\vspace{1cm}
\prob	$(x+6)(x-2)=(x-2)(x+6)$ &\prob	$a=a+0$\\
\vspace{1cm}
\prob	$(a^2b^3)^5=a^{10}b^{15}$ &\prob	$3+6=9$\\
\end{tabular}\\
\pagebreak

\vspace{1cm}
\textbf{Section III}  Give the name that best describes each item.  (3 pts. each)
\vspace{.5cm}\\

\begin{tabular}{ll}
\vspace{1cm}
\prob	The $18$ in $(3)(6)=18$ &\prob	$4t-t^2$\\
\vspace{1cm}
\prob	$4a-6=5b$ &\prob	$x\leq y$\\
\vspace{1cm}
\prob	The $4$ in $4b$ &\prob	The $b$ in $4b$\\
\vspace{1cm}
\prob	The $4b$ in $2b^2+4b=9$ \hspace{3cm} &\prob	The $17$ in $8+9=17$\\
\vspace{1cm}
\prob	$[0,4)$ &\prob	The $m$ in $b^m$\\
\vspace{1cm}
\end{tabular}\\

\vspace{1cm}
\textbf{Section IV}  Simplify.  (5 pts. each)
\vspace{.5cm}\\

\prob	$\frac{14}{9}(\frac{18x}{7})$\\

\vspace{5cm}
\prob $3x=6$\\

\vspace{5cm}
\prob $4t-2=10$\\

\vspace{5cm}
\prob $3x-x(2+\frac{1}{x})=3$\\

\vspace{5cm}
\prob $4(a+4)=2a-(3-a)$

\end{document}