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\begin{document}


\begin{tabular}{lr}
	Name:\underline{\hspace{8cm}}  & Math 095 Midterm II \\
	& \hspace{3cm} 3 October 2011
\end{tabular}

\textbf{Section I}  Plot the expression on the number line.  (3 pts. each)
\vspace{.5cm}\\

\begin{tabular}{ll}
	\prob	$x=\frac{4}{5}$ & \prob	$x \geq -1$ \\
	\vspace{1cm}

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	\hspace{2cm}
	&
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		\psaxes[subticks=0,labels=none]{<->}(0,0)(8,5)(-8,-5)%
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	\prob	$x \geq 0$ & \prob	$t \in [22,\infty)$ \\
	\vspace{1cm}
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	&
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		\psaxes[subticks=0,labels=none]{<->}(0,0)(8,5)(-8,-5)%
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	\prob	$-\infty < a < -1$  & \\
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	&\\
\end{tabular}\\

\vspace{1cm}
\textbf{Section II}  Perform the indicated operation. (5pts each)
\vspace{.5cm}\\

	\begin{tabular}{ll}
	\vspace{5cm}
	\prob	$(4x+2x^3+2x^2+3)-(4x^3+2x^2+x+9)$ &\prob	$(3x^3+2x^2+x)(x^2+2)$\\
	\vspace{5cm}
	\prob	$(2x+1)[(x^2+3x-8)+(x+4)]$ & \\
\end{tabular}\\

\textbf{Section III}  Solve. (5pts each)
\vspace{.5cm}\\

\begin{tabular}{ll}
	\vspace{3.5cm}
	\prob	$x+5=-11$ & \prob	$6a=24$ \\
	\vspace{3.5cm}
	\prob	$3x+5=-7$ & \prob	$6(a+2)=24$ \\
	\vspace{3.5cm}
	\prob	$\frac{3(x+5)}{4}=-9$ & \prob	$\frac{2}{3}(a+9)=24$ \\
	\vspace{3.5cm}
	\prob	$3x+5<-7$ & \prob	$-6(a+2)\leq24$ \\
	\vspace{3.5cm}
	\prob	$2m+22>m-5$ & \prob	$6(d+2)-4d\geq2-(3d+7)$ \\
\end{tabular}


\textbf{Section IV}  Simplify (10 points each)
\vspace{.5cm}\\

\begin{tabular}{p{8cm}l}
	\prob	$\frac{x^5-7x^3-4x^2-18x+36}{x^2-9}$ & \prob	Solve for I. \\
	\vspace{8cm} & $3(U-I)+2I>0$\\
\end{tabular}\\

\begin{quote}
``Even in the Valley of the Shadow of Death, two and two is not six.'' --- Leo Tolstoy
\end{quote}
\end{document}