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\begin{document}


\begin{tabular}{lr}
	Name:\underline{\hspace{8cm}}  & Math 095 Midterm II \\
	& \hspace{3cm} 3 October 2011
\end{tabular}

\textbf{Section I}  Plot the expression on the number line.  (3 pts. each)
\vspace{.5cm}\\

\begin{tabular}{ll}
	\prob	$x=\frac{3}{4}$ & \prob	$x \geq 1$ \\
	\vspace{1cm}

	\begin{pspicture}(-8,-0.5)(8,1)
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		\psaxes[subticks=0,labels=none]{<->}(0,0)(8,5)(-8,-5)%
	\end{pspicture}
	\hspace{2cm}
	&
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		\psset{yAxis=false}%
		\psaxes[subticks=0,labels=none]{<->}(0,0)(8,5)(-8,-5)%
	\end{pspicture}\\

	\prob	$x \leq 0$ & \prob	$t \in (8,\infty)$ \\
	\vspace{1cm}
	\begin{pspicture}(-8,-0.5)(8,1)
		\psset{yAxis=false}%
		\psaxes[subticks=0,labels=none]{<->}(0,0)(8,5)(-8,-5)%
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	&
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		\psset{yAxis=false}%
		\psaxes[subticks=0,labels=none]{<->}(0,0)(8,5)(-8,-5)%
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	\prob	$-3 \leq a < 2$  & \\
	\begin{pspicture}(-8,-0.5)(8,1)
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		\psaxes[subticks=0,labels=none]{<->}(0,0)(8,5)(-8,-5)%
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	&\\
\end{tabular}\\

\vspace{1cm}
\textbf{Section II}  Perform the indicated operation. (5pts each)
\vspace{.5cm}\\

	\begin{tabular}{ll}
	\vspace{5cm}
	\prob	$(x+4x^3+2x^2+6)-(4x^3+2x^2+2x+9)$ &\prob	$(3x^3+2x^2+x)(x^2+2)$\\
	\vspace{5cm}
	\prob	$(3x+1)[(x^2+3x-8)+(x-1)]$ & \\
\end{tabular}\\

\textbf{Section III}  Solve. (5pts each)
\vspace{.5cm}\\

\begin{tabular}{ll}
	\vspace{3.5cm}
	\prob	$x+3=-12$ & \prob	$3a=18$ \\
	\vspace{3.5cm}
	\prob	$3x+1=-5$ & \prob	$4(a+2)=12$ \\
	\vspace{3.5cm}
	\prob	$\frac{5(x+3)}{2}=15$ & \prob	$\frac{3}{4}(a+3)=16$ \\
	\vspace{3.5cm}
	\prob	$3x+1<-5$ & \prob	$-4(a+2)\leq 12$ \\
	\vspace{3.5cm}
	\prob	$2a+5>a-5$ & \prob	$3(d+5)-d\geq2-(d+7)$ \\
\end{tabular}


\textbf{Section IV}  Simplify (10 points each)
\vspace{.5cm}\\

\begin{tabular}{p{8cm}l}
	\prob	$\frac{2x^4+x^3+5x+4}{x^2+2x+1}$ & \prob	Solve for I. \\
	\vspace{8cm} & $3(U-I)+2I>0$\\
\end{tabular}\\

\begin{quote}
``Even in the Valley of the Shadow of Death, two and two is not six.'' --- Leo Tolstoy
\end{quote}
\end{document}