\documentclass[11pt]{article}
\usepackage{amsmath, amsthm, amssymb, amsthm, units, full page}
\usepackage{longtable}

\newcounter{prob_num}
\setcounter{prob_num}{1}
\newcommand{\prob}{\arabic{prob_num})  \stepcounter{prob_num}}

\begin{document}


\begin{tabular}{lr}
	Name:\underline{\hspace{8cm}}  & Math 095 Quiz 1 \\
	& \hspace{3cm} 13 September 2011
\end{tabular}

\textbf{Solve.} (30 points)
\vspace{.25cm}\\

\begin{longtable}{p{5cm}p{5cm}p{5cm}}
\vspace{3cm}
\prob  $a+m=b$ for $m$&
\prob  $dc=a$ for $d$&
\prob  $r-x=d$ for $x$\\
\vspace{3cm}
\prob  $\frac{m}{n}=b$ for $n$&
\prob  $m=r(a-b)$ for $r$&
\prob  $ax+m=y$ for $a$\\
\end{longtable}

\textbf{Write a formula to describe the value.} (10 points)
\vspace{.25cm}\\

\prob  Allison, Bob, and Charles are highly competitive apiarists!  Bob has as many bees as Allison and Charles combined. Write an expression for the number of bees Allison has ($a$) in terms of the number Charles and Bob have ($c$ and $b$ respectively).
\vspace{3cm}\\

\textbf{Simplify.} (60 points)
\vspace{.25cm}\\

\begin{longtable}{p{7.5cm} p{7.5cm}}
\vspace{4cm}
\prob $\sqrt{162}$ &
\prob $(a^nb^n)^m$ \\
\vspace{6cm}
\prob $(a^{mn})^{\frac{1}{n}}$ &
\prob $(x^2+2x-7)-(-2x^2+5x+2)$\\
\vspace{6cm}
\prob $(b+c^2+c)(ca-a)$ &
\prob $(m+am)^3$\\
\end{longtable}

\begin{quote}
``By this it appears how necessary it is for any man that aspires to true knowledge to examine the definitions of former authors.... For the errors of definitions multiply themselves, according as the reckoning proceeds, and lead men into absurdities, which at last they see, but cannot avoid, without reckoning anew from the beginning; in which lies the foundation of their errors.'' --- Thomas Hobbes, \textit{Leviathan}
\end{quote}

\end{document}